What is expand ((-1)^{k+1}*(k+1))8 ?

The solution to expand ((-1)^{k+1}*(k+1))8 is 8(-1)^{k+1}k+8(-1)^{k+1}

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expand ((-1)^{k+1}*(k+1))8

expand

((- 1)^{k + 1} \cdot (k + 1)) 8

8 (- 1)^{k + 1} k + 8 (- 1)^{k + 1}

Solution steps

((- 1)^{k + 1} (k + 1)) \cdot 8

Remove parentheses:

(a) = a

= (- 1)^{k + 1} (k + 1) \cdot 8

= 8 (- 1)^{k + 1} (k + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = (- 1)^{k + 1} \cdot 8, b = k, c = 1

= (- 1)^{k + 1} \cdot 8 k + (- 1)^{k + 1} \cdot 8 \cdot 1

= 8 (- 1)^{k + 1} k + 8 \cdot 1 \cdot (- 1)^{k + 1}

Multiply the numbers:

8 \cdot 1 = 8

= 8 (- 1)^{k + 1} k + 8 (- 1)^{k + 1}

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What is expand ((-1)^{k+1}*(k+1))8 ?
The solution to expand ((-1)^{k+1}*(k+1))8 is 8(-1)^{k+1}k+8(-1)^{k+1}