What is expand log_{10}(2)(4x^2+8x+4) ?

The solution to expand log_{10}(2)(4x^2+8x+4) is 4log_{10}(2)x^2+8log_{10}(2)x+4log_{10}(2)

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expand log_{10}(2)(4x^2+8x+4)

expand

lo g_{10} (2) (4 x^{2} + 8 x + 4)

4 lo g_{10} (2) x^{2} + 8 lo g_{10} (2) x + 4 lo g_{10} (2)

Solution steps

lo g_{10} (2) (4 x^{2} + 8 x + 4)

Apply the distributive law:

m (a + b + c) = ma + mb + m c

lo g_{10} (2) (4 x^{2} + 8 x + 4) = lo g_{10} (2) \cdot 4 x^{2} + lo g_{10} (2) \cdot 8 x + lo g_{10} (2) \cdot 4

= lo g_{10} (2) \cdot 4 x^{2} + lo g_{10} (2) \cdot 8 x + lo g_{10} (2) \cdot 4

Simplify

lo g_{10} (2) \cdot 4 x^{2} + lo g_{10} (2) \cdot 8 x + lo g_{10} (2) \cdot 4 : 4 lo g_{10} (2) x^{2} + 8 lo g_{10} (2) x + 4 lo g_{10} (2)

= 4 lo g_{10} (2) x^{2} + 8 lo g_{10} (2) x + 4 lo g_{10} (2)

\frac{K ( s ( s + 1 ) ( s + 5 ) )}{1 + K ( s ( s + 1 ) ( s + 5 ) )}

(- 7 + 2 a) \cdot e^{2 a - 4}

\frac{2 ( s ^{2} + 5 )}{s ( s - 4 ) ( s ^{2} + 4 )}

- 4 (e^{x} cos (x) - e^{x} sin (x))

\frac{1 + ( x ^{2} + 5 ) 4 x - 3}{x ^{2} + 5}

What is expand log_{10}(2)(4x^2+8x+4) ?
The solution to expand log_{10}(2)(4x^2+8x+4) is 4log_{10}(2)x^2+8log_{10}(2)x+4log_{10}(2)