What is expand (q-147^{1/3})^3 ?

The solution to expand (q-147^{1/3})^3 is q^3-3q^2*147^{1/3}+3q*147^{2/3}-147

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expand (q-147^{1/3})^3

expand

(q - 14 7^{\frac{1}{3}})^{3}

q^{3} - 3 q^{2} \cdot 14 7^{\frac{1}{3}} + 3 q \cdot 14 7^{\frac{2}{3}} - 147

Solution steps

(q - 14 7^{\frac{1}{3}})^{3}

Apply Perfect Cube Formula:

(a - b)^{3} = a^{3} - 3 a^{2} b + 3 a b^{2} - b^{3}

(q - 14 7^{\frac{1}{3}})^{3} = q^{3} - 3 q^{2} \cdot 14 7^{\frac{1}{3}} + 3 q (14 7^{\frac{1}{3}})^{2} - (14 7^{\frac{1}{3}})^{3}

= q^{3} - 3 q^{2} \cdot 14 7^{\frac{1}{3}} + 3 q (14 7^{\frac{1}{3}})^{2} - (14 7^{\frac{1}{3}})^{3}

(14 7^{\frac{1}{3}})^{2} = 14 7^{\frac{2}{3}}

(14 7^{\frac{1}{3}})^{3} = 147

= q^{3} - 3 q^{2} \cdot 14 7^{\frac{1}{3}} + 3 q \cdot 14 7^{\frac{2}{3}} - 147

(u d x + x d u) x^{2}

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\frac{5 ( x + 1 )}{x ^{2}}

l im x \Rightarrow 2 (3 x^{2} + x^{3}) \frac{3}{4}

\frac{s + 3}{( s + 1 ) ( s - 1 ) ( x + 2 ) ( 2 x + 1 )}

What is expand (q-147^{1/3})^3 ?
The solution to expand (q-147^{1/3})^3 is q^3-3q^2*147^{1/3}+3q*147^{2/3}-147