What is expand 1/16 (e^{4x}*4x-e^{4x}) ?

The solution to expand 1/16 (e^{4x}*4x-e^{4x}) is (e^{4x}x)/4-1/16 e^{4x}

Popular >

expand 1/16 (e^{4x}*4x-e^{4x})

expand

\frac{1}{16} (e^{4 x} \cdot 4 x - e^{4 x})

\frac{e ^{4 x} x}{4} - \frac{1}{16} e^{4 x}

Solution steps

\frac{1}{16} (e^{4 x} \cdot 4 x - e^{4 x})

= \frac{1}{16} (4 e^{4 x} x - e^{4 x})

Apply the distributive law:

a (b - c) = ab - a c

a = \frac{1}{16}, b = e^{4 x} \cdot 4 x, c = e^{4 x}

= \frac{1}{16} e^{4 x} \cdot 4 x - \frac{1}{16} e^{4 x}

= 4 \cdot \frac{1}{16} e^{4 x} x - \frac{1}{16} e^{4 x}

Simplify

4 \cdot \frac{1}{16} e^{4 x} x - \frac{1}{16} e^{4 x} : \frac{e ^{4 x} x}{4} - \frac{1}{16} e^{4 x}

= \frac{e ^{4 x} x}{4} - \frac{1}{16} e^{4 x}

\frac{2 ( 18 π + 16 ) 18 π + 16 - 128}{27}

\frac{( n + 1 ) ( 3 n + 7 )}{2}

\frac{a ^{2} + 8}{( a - 10 ) ( a + 10 )}

\frac{- 2 s ^{3} + 4 s ^{2} + 6 s + 18}{s ^{2} ( s ^{2} + 6 )}

cos (5) (1 - 4 x^{2})

What is expand 1/16 (e^{4x}*4x-e^{4x}) ?
The solution to expand 1/16 (e^{4x}*4x-e^{4x}) is (e^{4x}x)/4-1/16 e^{4x}