What are the solutions to the equation (x+2)^2=-25 ?

The solutions to the equation (x+2)^2=-25 are x=5i-2,x=-5i-2

Find the zeros of (x+2)^2=-25

The zeros of (x+2)^2=-25 are x=5i-2,x=-5i-2

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(x + 2)^{2} = - 25

x = 5 i - 2, x = - 5 i - 2

Solution steps

(x + 2)^{2} = - 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = - 25 : x = 5 i - 2

Solve

x + 2 = - - 25 : x = - 5 i - 2

The solutions to the quadratic equation are:

x = 5 i - 2, x = - 5 i - 2

- 5 x + 6 \leq - 4 x + 3

40 x = 8

\frac{3 x + 19}{2} = 5

18 x y^{2} - 12 x y + 2 x

- 5 (3 x - 4) = 20 - 15 x

What are the solutions to the equation (x+2)^2=-25 ?
The solutions to the equation (x+2)^2=-25 are x=5i-2,x=-5i-2
Find the zeros of (x+2)^2=-25
The zeros of (x+2)^2=-25 are x=5i-2,x=-5i-2