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Popular >

d/(dq)((c)(0.0003q^2-0.03q+4))

Solution

\frac{d}{d q} ((c) (0.0003 q^{2} - 0.03 q + 4))

Solution

c (0.0006 q - 0.03)

Solution steps

\frac{d}{d q} ((c) (0.0003 q^{2} - 0.03 q + 4))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= c \frac{d}{d q} (0.0003 q^{2} - 0.03 q + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= c (\frac{d}{d q} (0.0003 q^{2}) - \frac{d}{d q} (0.03 q) + \frac{d}{d q} (4))

\frac{d}{d q} (0.0003 q^{2}) = 0.0006 q

\frac{d}{d q} (0.03 q) = 0.03

\frac{d}{d q} (4) = 0

= c (0.0006 q - 0.03 + 0)

Simplify

= c (0.0006 q - 0.03)

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Frequently Asked Questions (FAQ)

What is the d/(dq)((c)(0.0003q^2-0.03q+4)) ?
The d/(dq)((c)(0.0003q^2-0.03q+4)) is c(0.0006q-0.03)
What is the first d/(dq)((c)(0.0003q^2-0.03q+4)) ?
The first d/(dq)((c)(0.0003q^2-0.03q+4)) is c(0.0006q-0.03)