What is expand (2ω(ω^2-4))/(-7ω^2+3) ?

The solution to expand (2ω(ω^2-4))/(-7ω^2+3) is (2ω^3-8ω)/(-7ω^2+3)

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expand (2ω(ω^2-4))/(-7ω^2+3)

expand

\frac{2 ω ( ω ^{2} - 4 )}{- 7 ω ^{2} + 3}

\frac{2 ω ^{3} - 8 ω}{- 7 ω ^{2} + 3}

Solution steps

\frac{2 ω ( ω ^{2} - 4 )}{- 7 ω ^{2} + 3}

Expand

2 ω (ω^{2} - 4) : 2 ω^{3} - 8 ω

= \frac{2 ω ^{3} - 8 ω}{- 7 ω ^{2} + 3}

\frac{( s + 1 )}{( s ^{2} - 4 ) ( s + 5 )}

\frac{- 3 x ^{2} + 2 x + 12}{( x - 2 ) ( x + 2 ) ( x + 1 )}

2 x (1 - ln (x))

(x + 1 + i)^{4}

\frac{3 ( - \frac{7}{8} ) ^{n} + 5}{17}

What is expand (2ω(ω^2-4))/(-7ω^2+3) ?
The solution to expand (2ω(ω^2-4))/(-7ω^2+3) is (2ω^3-8ω)/(-7ω^2+3)