What is expand (x^4-9)(dy)/(dx)+x^3y ?

The solution to expand (x^4-9)(dy)/(dx)+x^3y is x^4(dy)/(dx)-9(dy)/(dx)+x^3y

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expand (x^4-9)(dy)/(dx)+x^3y

expand

(x^{4} - 9) \frac{d y}{d x} + x^{3} y

x^{4} \frac{d y}{d x} - 9 \frac{d y}{d x} + x^{3} y

Solution steps

(x^{4} - 9) \frac{d y}{d x} + x^{3} y

Expand

\frac{d y}{d x} (x^{4} - 9) : x^{4} \frac{d y}{d x} - 9 \frac{d y}{d x}

= x^{4} \frac{d y}{d x} - 9 \frac{d y}{d x} + x^{3} y

x - 3 (3 (x + h)^{2} - 2 x + 2 h)

\frac{1}{( 1 + x ^{2} ) \cdot ( x ^{2} + x + 1 )}

\frac{24 ( s + 9 )}{( s + 0.8 ) ( s + 27 )}

\frac{( sin ( 2 x ) + 2 cos ( x ) ) \cdot 13}{169 + 6 π sin ( x )}

(e^{17 x} - e^{- 15 x})^{2}

What is expand (x^4-9)(dy)/(dx)+x^3y ?
The solution to expand (x^4-9)(dy)/(dx)+x^3y is x^4(dy)/(dx)-9(dy)/(dx)+x^3y