What is expand sin(t)u(t-3) ?

The solution to expand sin(t)u(t-3) is tusin(t)-3usin(t)

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expand sin(t)u(t-3)

expand

sin (t) u (t - 3)

t u sin (t) - 3 u sin (t)

Solution steps

sin (t) u (t - 3)

= u sin (t) (t - 3)

Apply the distributive law:

a (b - c) = ab - a c

u sin (t) (t - 3) = u sin (t) t - u sin (t) \cdot 3

= u sin (t) t - u sin (t) \cdot 3

= t u sin (t) - 3 u sin (t)

(2 x^{3} - 3 x^{2} + 4 x) (7 x + \frac{2}{9})

\frac{1}{( 1 - x )}

3 \cdot (9 + 75)^{7}

\frac{( 24 x - 7 y ) ^{2}}{625}

\frac{3 s ^{3} + s ^{2} - 3 s + 6}{s ^{2} ( s ^{2} + 16 )}

What is expand sin(t)u(t-3) ?
The solution to expand sin(t)u(t-3) is tusin(t)-3usin(t)