What are the solutions to the equation x^2-3x+28=0 ?

The solutions to the equation x^2-3x+28=0 are x= 3/2+i(sqrt(103))/2 ,x= 3/2-i(sqrt(103))/2

Find the zeros of x^2-3x+28=0

The zeros of x^2-3x+28=0 are x= 3/2+i(sqrt(103))/2 ,x= 3/2-i(sqrt(103))/2

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x^{2} - 3 x + 28 = 0

x = \frac{3}{2} + i \frac{103}{2}, x = \frac{3}{2} - i \frac{103}{2}

Solution steps

x^{2} - 3 x + 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 28}{2 \cdot 1}

Simplify

(- 3)^{2} - 4 \cdot 1 \cdot 28 : 103 i

x_{1, 2} = \frac{- ( - 3 ) \pm 103 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 103 i}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 103 i}{2 \cdot 1}

x = \frac{- ( - 3 ) + 103 i}{2 \cdot 1} : \frac{3}{2} + i \frac{103}{2}

x = \frac{- ( - 3 ) - 103 i}{2 \cdot 1} : \frac{3}{2} - i \frac{103}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{103}{2}, x = \frac{3}{2} - i \frac{103}{2}

285 \cdot \frac{π}{180}

x^{4} + 5 x^{3} - 14 x^{2}

∣ 3 x - 2 ∣ > ∣ x + 2 ∣

\frac{\frac{π}{3}}{2}

- ∣ x ∣ > 4

What are the solutions to the equation x^2-3x+28=0 ?
The solutions to the equation x^2-3x+28=0 are x= 3/2+i(sqrt(103))/2 ,x= 3/2-i(sqrt(103))/2
Find the zeros of x^2-3x+28=0
The zeros of x^2-3x+28=0 are x= 3/2+i(sqrt(103))/2 ,x= 3/2-i(sqrt(103))/2