What is expand 1/3 (x+6=5(x/3-4)) ?

The solution to expand 1/3 (x+6=5(x/3-4)) is x/3+2=(5x)/3-20

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expand 1/3 (x+6=5(x/3-4))

expand

\frac{1}{3} (x + 6 = 5 (\frac{x}{3} - 4))

\frac{x}{3} + 2 = \frac{5 x}{3} - 20

Solution steps

\frac{1}{3} (x + 6 = 5 (\frac{x}{3} - 4))

= \frac{1}{3} (x + 6 \cdot 5 = (\frac{x}{3} - 4))

Apply the distributive law:

a (b + c) = ab + a c

a = \frac{1}{3}, b = x, c = 6 = 5 (\frac{x}{3} - 4)

\frac{1}{3} x + \frac{1}{3} \cdot 6 = 5 (\frac{x}{3} - 4)

\frac{1}{3} x + 6 \cdot \frac{1}{3} = 5 (\frac{x}{3} - 4)

Simplify

\frac{1}{3} x + 6 \cdot \frac{1}{3} = 5 (\frac{x}{3} - 4) : \frac{x}{3} + 2 = \frac{5 x}{3} - 20

\frac{x}{3} + 2 = \frac{5 x}{3} - 20

(2 (x - 3))^{2} + 4

- 125 (- 0.2 e^{- 0.2 t} t - e^{- 0.2 t})

(- 5 = 4 u + 2 y (u)) (- 9)

\frac{( 10 - 5 j ) ( 8 + 6 j )}{18 + j}

n u mb er a (x - 1) (x - 5)^{3} + 10

What is expand 1/3 (x+6=5(x/3-4)) ?
The solution to expand 1/3 (x+6=5(x/3-4)) is x/3+2=(5x)/3-20