What is expand ((x-3)(x+3))/((x+2)(x-2)) ?

The solution to expand ((x-3)(x+3))/((x+2)(x-2)) is (x^2-9)/(x^2-4)

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expand ((x-3)(x+3))/((x+2)(x-2))

expand

\frac{( x - 3 ) ( x + 3 )}{( x + 2 ) ( x - 2 )}

\frac{x ^{2} - 9}{x ^{2} - 4}

Solution steps

\frac{( x - 3 ) ( x + 3 )}{( x + 2 ) ( x - 2 )}

Expand

(x + 2) (x - 2) : x^{2} - 4

= \frac{( x - 3 ) ( x + 3 )}{x ^{2} - 4}

Expand

(x - 3) (x + 3) : x^{2} - 9

= \frac{x ^{2} - 9}{x ^{2} - 4}

p (x, y) (t = - \frac{7 π}{6})

- 3 (x + 2) (x - 2)

\frac{1}{( k + 1 ) ln ( k + 1 )}

\frac{x y}{y ^{- 1}}

What is expand ((x-3)(x+3))/((x+2)(x-2)) ?
The solution to expand ((x-3)(x+3))/((x+2)(x-2)) is (x^2-9)/(x^2-4)