What are the solutions to the equation 2(x-1)^2+1=4 ?

The solutions to the equation 2(x-1)^2+1=4 are x=sqrt(3/2)+1,x=-sqrt(3/2)+1

Find the zeros of 2(x-1)^2+1=4

The zeros of 2(x-1)^2+1=4 are x=sqrt(3/2)+1,x=-sqrt(3/2)+1

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2 (x - 1)^{2} + 1 = 4

x = \frac{3}{2} + 1, x = - \frac{3}{2} + 1

Decimal Notation

x = 2.22474 \dots, x = - 0.22474 \dots

Solution steps

2 (x - 1)^{2} + 1 = 4

Move

1

to the right side

2 (x - 1)^{2} = 3

Divide both sides by

2

(x - 1)^{2} = \frac{3}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = \frac{3}{2} : x = \frac{3}{2} + 1

Solve

x - 1 = - \frac{3}{2} : x = - \frac{3}{2} + 1

The solutions to the quadratic equation are:

x = \frac{3}{2} + 1, x = - \frac{3}{2} + 1

e^{- \frac{1}{0}}

x^{\frac{9}{2}}

3^{∣ x - 2 ∣} > 9^{x}

\frac{1}{3} (5 x - 1) \geq \frac{3}{7} (x + 5)

8 y^{3} + 14 y^{2} + 3 y

What are the solutions to the equation 2(x-1)^2+1=4 ?
The solutions to the equation 2(x-1)^2+1=4 are x=sqrt(3/2)+1,x=-sqrt(3/2)+1
Find the zeros of 2(x-1)^2+1=4
The zeros of 2(x-1)^2+1=4 are x=sqrt(3/2)+1,x=-sqrt(3/2)+1