What is expand (3m+(12)/(m^2)= 3/2 m-1/2 m^2)m^2 ?

The solution to expand (3m+(12)/(m^2)= 3/2 m-1/2 m^2)m^2 is 3m^3+12=(3m)/2-(m^4)/2

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expand (3m+(12)/(m^2)= 3/2 m-1/2 m^2)m^2

expand

(3 m + \frac{12}{m ^{2}} = \frac{3}{2} m - \frac{1}{2} m^{2}) m^{2}

3 m^{3} + 12 = \frac{3 m}{2} - \frac{m ^{4}}{2}

Solution steps

(3 m + \frac{12}{m ^{2}} = \frac{3}{2} m - \frac{1}{2} m^{2}) m^{2}

= (3 m + \frac{3}{2} = \frac{12}{m ^{2}} m - \frac{1}{2} m^{2}) m^{2}

Distribute parentheses

m^{2} \cdot 3 m + m^{2} \frac{12}{m ^{2}} = \frac{3}{2} m + m^{2} (- \frac{1}{2} m^{2})

Apply minus-plus rules

+ (- a) = - a

3 m^{2} m + \frac{12}{m ^{2}} m^{2} = \frac{3}{2} m - \frac{1}{2} m^{2} m^{2}

Simplify

3 m^{2} m + \frac{12}{m ^{2}} m^{2} = \frac{3}{2} m - \frac{1}{2} m^{2} m^{2} : 3 m^{3} + 12 = \frac{3 m}{2} - \frac{m ^{4}}{2}

3 m^{3} + 12 = \frac{3 m}{2} - \frac{m ^{4}}{2}

e^{x} sin (2 x) (e^{x} cos (2 x) - 2 e^{x} sin (2 x))

m (m - n)

(x + 3) 4 (x - 2 + 7) (x + 2 - 7)

(\frac{x}{3} + 3 y) (\frac{x}{4} + 2 y)

\frac{2 x}{( x - 3 ) ^{4} - y ^{4}}

What is expand (3m+(12)/(m^2)= 3/2 m-1/2 m^2)m^2 ?
The solution to expand (3m+(12)/(m^2)= 3/2 m-1/2 m^2)m^2 is 3m^3+12=(3m)/2-(m^4)/2