What are the solutions to the equation y-5=y^2-y-9 ?

The solutions to the equation y-5=y^2-y-9 are y=1+sqrt(5),y=1-sqrt(5)

Find the zeros of y-5=y^2-y-9

The zeros of y-5=y^2-y-9 are y=1+sqrt(5),y=1-sqrt(5)

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y - 5 = y^{2} - y - 9

y = 1 + 5, y = 1 - 5

Solution steps

y - 5 = y^{2} - y - 9

Switch sides

y^{2} - y - 9 = y - 5

Move

5

to the left side

y^{2} - y - 4 = y

Move

y

to the left side

y^{2} - 2 y - 4 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 4) = 25

y_{1, 2} = \frac{- ( - 2 ) \pm 2 5}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 2 ) + 2 5}{2 \cdot 1}, y_{2} = \frac{- ( - 2 ) - 2 5}{2 \cdot 1}

y = \frac{- ( - 2 ) + 2 5}{2 \cdot 1} : 1 + 5

y = \frac{- ( - 2 ) - 2 5}{2 \cdot 1} : 1 - 5

The solutions to the quadratic equation are:

y = 1 + 5, y = 1 - 5

2 (x + 7) - 3 (4 x + 3) = 1

2 u - 5 > 4 u - 13

x - 9 < - 15

- 3 x \geq 12

4 (x + 2) (x - 2) = (2 x)^{2} + 8 x

What are the solutions to the equation y-5=y^2-y-9 ?
The solutions to the equation y-5=y^2-y-9 are y=1+sqrt(5),y=1-sqrt(5)
Find the zeros of y-5=y^2-y-9
The zeros of y-5=y^2-y-9 are y=1+sqrt(5),y=1-sqrt(5)