What is expand 112(((x+2)^2)/7+((y+5)^2)/(16)=1) ?

The solution to expand 112(((x+2)^2)/7+((y+5)^2)/(16)=1) is 16x^2+64x+7y^2+70y+239=1

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expand 112(((x+2)^2)/7+((y+5)^2)/(16)=1)

expand

112 (\frac{( x + 2 ) ^{2}}{7} + \frac{( y + 5 ) ^{2}}{16} = 1)

16 x^{2} + 64 x + 7 y^{2} + 70 y + 239 = 1

Solution steps

112 (\frac{( x + 2 ) ^{2}}{7} + \frac{( y + 5 ) ^{2}}{16} = 1)

= 112 (\frac{( x + 2 ) ^{2}}{7} + 1 = \frac{( y + 5 ) ^{2}}{16})

Apply the distributive law:

a (b + c) = ab + a c

a = 112, b = \frac{( x + 2 ) ^{2}}{7}, c = \frac{( y + 5 ) ^{2}}{16} = 1

112 \cdot \frac{( x + 2 ) ^{2}}{7} + 112 \cdot \frac{( y + 5 ) ^{2}}{16} = 1

Expand

112 \cdot \frac{( x + 2 ) ^{2}}{7} + 112 \cdot \frac{( y + 5 ) ^{2}}{16} : 16 x^{2} + 64 x + 7 y^{2} + 70 y + 239

16 x^{2} + 64 x + 7 y^{2} + 70 y + 239 = 1

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A (4, - 2) y B (0, 6)

\frac{d}{d x} ((160 - 24 x) (x - 4)) - 950

(x_{0} + α x_{1})^{2}

\frac{2}{ln ( 3 ) ( x - 3 ) ^{3}}

What is expand 112(((x+2)^2)/7+((y+5)^2)/(16)=1) ?
The solution to expand 112(((x+2)^2)/7+((y+5)^2)/(16)=1) is 16x^2+64x+7y^2+70y+239=1