What is expand (3^{coth(x)}-tan(6x))^2 ?

The solution to expand (3^{coth(x)}-tan(6x))^2 is 9^{coth(x)}-2*3^{coth(x)}tan(6x)+tan^2(6x)

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expand (3^{coth(x)}-tan(6x))^2

expand

(3^{c o t h (x)} - tan (6 x))^{2}

9^{c o t h (x)} - 2 \cdot 3^{c o t h (x)} tan (6 x) + tan^{2} (6 x)

Solution steps

(3^{c o t h (x)} - tan (6 x))^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(3^{c o t h (x)} - tan (6 x))^{2} = (3^{c o t h (x)})^{2} - 2 \cdot 3^{c o t h (x)} tan (6 x) + tan^{2} (6 x)

= (3^{c o t h (x)})^{2} - 2 \cdot 3^{c o t h (x)} tan (6 x) + tan^{2} (6 x)

Simplify

(3^{c o t h (x)})^{2} : 9^{c o t h (x)}

= 9^{c o t h (x)} - 2 \cdot 3^{c o t h (x)} tan (6 x) + tan^{2} (6 x)

cos (x) (- ln (tan (x) + sec (x)) + sin (x))

(9 + \frac{14}{x - 2}) (x - 2)

\frac{( 6 + 10 x - 4 x ^{2} ) ^{2}}{( 2 - x ) \cdot ( 3 - 3 x ) ^{3}}

\frac{2 ( 1 - x ^{\frac{3}{2}} ) ^{2}}{3}

sin (2) (π - x)

What is expand (3^{coth(x)}-tan(6x))^2 ?
The solution to expand (3^{coth(x)}-tan(6x))^2 is 9^{coth(x)}-2*3^{coth(x)}tan(6x)+tan^2(6x)