What is expand 2tan(x+y)sec^2(x+y)(1+z) ?

The solution to expand 2tan(x+y)sec^2(x+y)(1+z) is 2sec^2(x+y)tan(x+y)+2zsec^2(x+y)tan(x+y)

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expand 2tan(x+y)sec^2(x+y)(1+z)

expand

2 tan (x + y) sec^{2} (x + y) (1 + z)

2 sec^{2} (x + y) tan (x + y) + 2 z sec^{2} (x + y) tan (x + y)

Solution steps

2 tan (x + y) sec^{2} (x + y) (1 + z)

= 2 sec^{2} (x + y) tan (x + y) (1 + z)

Apply the distributive law:

a (b + c) = ab + a c

2 sec^{2} (x + y) tan (x + y) (1 + z) = 2 sec^{2} (x + y) tan (x + y) \cdot 1 + 2 sec^{2} (x + y) tan (x + y) z

= 2 sec^{2} (x + y) tan (x + y) \cdot 1 + 2 sec^{2} (x + y) tan (x + y) z

Simplify

2 sec^{2} (x + y) tan (x + y) \cdot 1 + 2 sec^{2} (x + y) tan (x + y) z : 2 sec^{2} (x + y) tan (x + y) + 2 z sec^{2} (x + y) tan (x + y)

= 2 sec^{2} (x + y) tan (x + y) + 2 z sec^{2} (x + y) tan (x + y)

\frac{26}{( s + 1 ) ^{3}}

(x + 3) (x - 2 - 3)

x \cdot 10 x

4 (3 x^{2} + 3 x - 1)^{3}

x (1 - x)

What is expand 2tan(x+y)sec^2(x+y)(1+z) ?
The solution to expand 2tan(x+y)sec^2(x+y)(1+z) is 2sec^2(x+y)tan(x+y)+2zsec^2(x+y)tan(x+y)