What is expand (18(216n^2-162n-54))/(n^2) ?

The solution to expand (18(216n^2-162n-54))/(n^2) is 3888-(2916)/n-(972)/(n^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (18(216n^2-162n-54))/(n^2)

expand

\frac{18 ( 216 n ^{2} - 162 n - 54 )}{n ^{2}}

3888 - \frac{2916}{n} - \frac{972}{n ^{2}}

Solution steps

\frac{18 ( 216 n ^{2} - 162 n - 54 )}{n ^{2}}

Expand

18 (216 n^{2} - 162 n - 54) : 3888 n^{2} - 2916 n - 972

= \frac{3888 n ^{2} - 2916 n - 972}{n ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{3888 n ^{2} - 2916 n - 972}{n ^{2}} = \frac{3888 n ^{2}}{n ^{2}} - \frac{2916 n}{n ^{2}} - \frac{972}{n ^{2}}

= \frac{3888 n ^{2}}{n ^{2}} - \frac{2916 n}{n ^{2}} - \frac{972}{n ^{2}}

Cancel

\frac{3888 n ^{2}}{n ^{2}} : 3888

= 3888 - \frac{2916 n}{n ^{2}} - \frac{972}{n ^{2}}

Cancel

\frac{2916 n}{n ^{2}} : \frac{2916}{n}

= 3888 - \frac{2916}{n} - \frac{972}{n ^{2}}

\frac{d}{d x} ((2) (a x e^{- 2 x} + 6))

\frac{e ^{- s}}{s ^{3} ( s ^{2} + 1 )}

(2 x - 5) \cdot e^{x}

\frac{π ^{2} ( - 1 ) ^{n} n ^{2} - 2 ( - 1 ) ^{n} + 2}{n ^{3}}

sin (θ) - cos (θ) (sin (θ) + cos (θ))

What is expand (18(216n^2-162n-54))/(n^2) ?
The solution to expand (18(216n^2-162n-54))/(n^2) is 3888-(2916)/n-(972)/(n^2)