What is expand Cx^{4n}(x^{1/4}-1) ?

The solution to expand Cx^{4n}(x^{1/4}-1) is Cx^{(16n+1)/4}-Cx^{4n}

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expand Cx^{4n}(x^{1/4}-1)

expand

C x^{4 n} (x^{\frac{1}{4}} - 1)

C x^{\frac{16 n + 1}{4}} - C x^{4 n}

Solution steps

C x^{4 n} (x^{\frac{1}{4}} - 1)

Apply the distributive law:

a (b - c) = ab - a c

C x^{4 n} (x^{\frac{1}{4}} - 1) = C x^{4 n} x^{\frac{1}{4}} - C x^{4 n} \cdot 1

= C x^{4 n} x^{\frac{1}{4}} - C x^{4 n} \cdot 1

C x^{4 n} x^{\frac{1}{4}} = C x^{\frac{16 n + 1}{4}}

C x^{4 n} \cdot 1 = C x^{4 n}

= C x^{\frac{16 n + 1}{4}} - C x^{4 n}

\frac{2 s ^{3} + 10 s + 3}{s ^{2} ( s + 1 ) ( s + 2 )}

\frac{( a + 2 ) ( a ^{2} - 2 a )}{( a ^{2} - 16 ) ( 5 a + 2 )}

2 (5 + 7)

- 7 (x + 6 y = 27)

\frac{e ^{- p}}{( p + 1 ) ^{2}}

What is expand Cx^{4n}(x^{1/4}-1) ?
The solution to expand Cx^{4n}(x^{1/4}-1) is Cx^{(16n+1)/4}-Cx^{4n}