What are the solutions to the equation 2x^2+100=0 ?

The solutions to the equation 2x^2+100=0 are x=sqrt(2)*5i,x=-sqrt(2)*5i

Find the zeros of 2x^2+100=0

The zeros of 2x^2+100=0 are x=sqrt(2)*5i,x=-sqrt(2)*5i

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2 x^{2} + 100 = 0

x = 2 \cdot 5 i, x = - 2 \cdot 5 i

Solution steps

2 x^{2} + 100 = 0

Move

100

to the right side

2 x^{2} = - 100

Divide both sides by

2

x^{2} = - 50

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 50, x = - - 50

- 50 = 2 \cdot 5 i

- - 50 = - 2 \cdot 5 i

x = 2 \cdot 5 i, x = - 2 \cdot 5 i

\frac{7 !}{( 7 - 3 ) ! 3 !}

- y + 12 - 2 y = 3

7 = 8 n

- 4 x + 8

2 d^{3} - 432 q^{3}

What are the solutions to the equation 2x^2+100=0 ?
The solutions to the equation 2x^2+100=0 are x=sqrt(2)*5i,x=-sqrt(2)*5i
Find the zeros of 2x^2+100=0
The zeros of 2x^2+100=0 are x=sqrt(2)*5i,x=-sqrt(2)*5i