What is expand (2x^2-2xsqrt(x^2+1)+2)(1+x^2) ?

The solution to expand (2x^2-2xsqrt(x^2+1)+2)(1+x^2) is 2x^4+4x^2-2xsqrt(x^2+1)-2x^3sqrt(x^2+1)+2

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expand (2x^2-2xsqrt(x^2+1)+2)(1+x^2)

expand

(2 x^{2} - 2 x x^{2} + 1 + 2) (1 + x^{2})

2 x^{4} + 4 x^{2} - 2 x x^{2} + 1 - 2 x^{3} x^{2} + 1 + 2

Solution steps

(2 x^{2} - 2 x x^{2} + 1 + 2) (1 + x^{2})

Distribute parentheses

= 2 x^{2} \cdot 1 + 2 x^{2} x^{2} - 2 x x^{2} + 1 \cdot 1 - 2 x x^{2} + 1 x^{2} + 2 \cdot 1 + 2 x^{2}

Simplify

2 x^{2} \cdot 1 + 2 x^{2} x^{2} - 2 x x^{2} + 1 \cdot 1 - 2 x x^{2} + 1 x^{2} + 2 \cdot 1 + 2 x^{2} : 2 x^{4} + 4 x^{2} - 2 x x^{2} + 1 - 2 x^{3} x^{2} + 1 + 2

= 2 x^{4} + 4 x^{2} - 2 x x^{2} + 1 - 2 x^{3} x^{2} + 1 + 2

(4 - 2 x) (5 - 3 x)

\frac{x ^{2} - 25 ( x ^{2} + 1 )}{x ^{2}}

(z + \frac{4}{3})^{2} - \frac{25}{9}

\frac{( x + 1 ) ^{2}}{4 ^{x + 1}} - \frac{x ^{2}}{4 ^{x}}

π (2 x + 4)^{2}

What is expand (2x^2-2xsqrt(x^2+1)+2)(1+x^2) ?
The solution to expand (2x^2-2xsqrt(x^2+1)+2)(1+x^2) is 2x^4+4x^2-2xsqrt(x^2+1)-2x^3sqrt(x^2+1)+2