What is 2x^2(-1/x+1) ?

The solution to 2x^2(-1/x+1) is 2x(x-1)

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simplify 2x^2(-1/x+1)

simplify

2 x^{2} (- \frac{1}{x} + 1)

2 x (x - 1)

Solution steps

2 x^{2} (- \frac{1}{x} + 1)

Join

- \frac{1}{x} + 1 : \frac{x - 1}{x}

= 2 x^{2} \frac{x - 1}{x}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 x ^{2} ( x - 1 )}{x}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

x^{2} = xx

= \frac{2 xx ( x - 1 )}{x}

Cancel the common factor:

x

= 2 x (x - 1)

(x + 1) (x + \frac{1}{2}) (x + \frac{1}{4})

(\frac{13}{2} - \frac{2 2 - 1}{3})

(x + h + h)^{2}

(x - \frac{1}{x})^{4} (x + \frac{1}{x})^{2}

\frac{c ( x - 5 )}{x ^{2} + a x + b}