What is expand (yx^{-3}=(x^4)/2+c)(2x^3) ?

The solution to expand (yx^{-3}=(x^4)/2+c)(2x^3) is 2y=(x^4)/2+2cx^3

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expand (yx^{-3}=(x^4)/2+c)(2x^3)

expand

(y x^{- 3} = \frac{x ^{4}}{2} + c) (2 x^{3})

2 y = \frac{x ^{4}}{2} + 2 c x^{3}

Solution steps

(y x^{- 3} = \frac{x ^{4}}{2} + c) (2 x^{3})

= (= y x^{- 3} \frac{x ^{4}}{2} + c) (2 x^{3})

Apply the distributive law:

a (b + c) = ab + a c

a = (2 x^{3}), b = y x^{- 3} = \frac{x ^{4}}{2}, c = c

(2 x^{3}) y x^{- 3} = \frac{x ^{4}}{2} + (2 x^{3}) c

y x^{- 3} (2 x^{3}) = \frac{x ^{4}}{2} + c (2 x^{3})

Simplify

y x^{- 3} (2 x^{3}) = \frac{x ^{4}}{2} + c (2 x^{3}) : 2 y = \frac{x ^{4}}{2} + 2 c x^{3}

2 y = \frac{x ^{4}}{2} + 2 c x^{3}

l im x \Rightarrow 2 (x^{2} + 3 x - 4)

(x^{2} + x + 1)^{10}

\frac{1}{( 3 x - 1 ) ^{4}}

c u r l (2 x - 2 z x^{2}, 2 z - x y, 9 z^{2} x^{2})

h (x) (x + 2) (1 - x)

What is expand (yx^{-3}=(x^4)/2+c)(2x^3) ?
The solution to expand (yx^{-3}=(x^4)/2+c)(2x^3) is 2y=(x^4)/2+2cx^3