What is (4x^2+2x-7\circ 2x-1)(x) ?

The solution to (4x^2+2x-7\circ 2x-1)(x) is x(4x^2+2x-14\circ x-1)

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simplify (4x^2+2x-7\circ 2x-1)(x)

simplify

(4 x^{2} + 2 x - 7 \circ 2 x - 1) (x)

x (4 x^{2} + 2 x - 14 \circ x - 1)

Solution steps

(4 x^{2} + 2 x - 7 \circ 2 x - 1) (x)

Remove parentheses:

(a) = a

= (4 x^{2} + 2 x - 7 \circ 2 x - 1) x

Multiply the numbers:

7 \cdot 2 = 14

= x (4 x^{2} + 2 x - 14 \circ x - 1)

y + 4 (- 3 = - 7)

10 (5 + 5)

e^{3 t^{5}} (2 t^{3} + 3)

\frac{( x - 9 ) ( x + 9 )}{x ^{3} - 27}

(x^{2} - 2 x + 1) d x

What is (4x^2+2x-7\circ 2x-1)(x) ?
The solution to (4x^2+2x-7\circ 2x-1)(x) is x(4x^2+2x-14\circ x-1)