en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((x-1)(x-2)(x-3))/((x-4)(x-5)(x-6))

Solution

expand

\frac{( x - 1 ) ( x - 2 ) ( x - 3 )}{( x - 4 ) ( x - 5 ) ( x - 6 )}

Solution

\frac{x ^{3} - 6 x ^{2} + 11 x - 6}{x ^{3} - 15 x ^{2} + 74 x - 120}

Solution steps

\frac{( x - 1 ) ( x - 2 ) ( x - 3 )}{( x - 4 ) ( x - 5 ) ( x - 6 )}

Expand

(x - 4) (x - 5) (x - 6) : x^{3} - 15 x^{2} + 74 x - 120

= \frac{( x - 1 ) ( x - 2 ) ( x - 3 )}{x ^{3} - 15 x ^{2} + 74 x - 120}

Expand

(x - 1) (x - 2) (x - 3) : x^{3} - 6 x^{2} + 11 x - 6

= \frac{x ^{3} - 6 x ^{2} + 11 x - 6}{x ^{3} - 15 x ^{2} + 74 x - 120}

Popular Examples

expand 3^{2(k+1)}expand

3^{2 (k + 1)}

expand-3e^{-x/3}x^2+6(-3e^{-x/3}x-9e^{-x/3})+C expand

- 3 e^{- \frac{x}{3}} x^{2} + 6 (- 3 e^{- \frac{x}{3}} x - 9 e^{- \frac{x}{3}}) + C

expand derivative of (x-3(x-6)^3)+7 expand

\frac{d}{d x} ((x - 3) (x - 6)^{3}) + 7

expand (1-piR)2Y expand

(1 - π R) 2 Y

expand (e^{-3t}+e^{-2t})u(t)expand

(e^{- 3 t} + e^{- 2 t}) u (t)

Frequently Asked Questions (FAQ)

What is expand ((x-1)(x-2)(x-3))/((x-4)(x-5)(x-6)) ?
The solution to expand ((x-1)(x-2)(x-3))/((x-4)(x-5)(x-6)) is (x^3-6x^2+11x-6)/(x^3-15x^2+74x-120)