What is (log_{10}((x+1)(x+4)))/((2x+23))-1 ?

The solution to (log_{10}((x+1)(x+4)))/((2x+23))-1 is (log_{10}(x+1)+log_{10}(x+4))/(2x+23)-1

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simplify (log_{10}((x+1)(x+4)))/((2x+23))-1

simplify

\frac{lo g _{10} ( ( x + 1 ) ( x + 4 ) )}{( 2 x + 23 )} - 1

\frac{lo g _{10} ( x + 1 ) + lo g _{10} ( x + 4 )}{2 x + 23} - 1

Solution steps

\frac{lo g _{10} ( ( x + 1 ) ( x + 4 ) )}{2 x + 23} - 1

Apply log rule:

lo g_{a} (x y) = lo g_{a} (x) + lo g_{a} (y)

lo g_{10} ((x + 1) (x + 4)) = lo g_{10} (x + 1) + lo g_{10} (x + 4)

= \frac{lo g _{10} ( x + 1 ) + lo g _{10} ( x + 4 )}{2 x + 23} - 1

y, 3 x - y = - 22

(x - y = 3, y) (2 x + 4 y = 9)

(\frac{1}{5}) (- 7^{n}) (1 + 5 x)

(X - \frac{1}{2})^{4}

\frac{\partial}{\partial u} ((x) (- 3 u - 3 v^{2}))

What is (log_{10}((x+1)(x+4)))/((2x+23))-1 ?
The solution to (log_{10}((x+1)(x+4)))/((2x+23))-1 is (log_{10}(x+1)+log_{10}(x+4))/(2x+23)-1