What are the solutions to the equation 24^2+10^2=c^2 ?

The solutions to the equation 24^2+10^2=c^2 are c=26,c=-26

Find the zeros of 24^2+10^2=c^2

The zeros of 24^2+10^2=c^2 are c=26,c=-26

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 4^{2} + 1 0^{2} = c^{2}

c = 26, c = - 26

Solution steps

2 4^{2} + 1 0^{2} = c^{2}

Switch sides

c^{2} = 2 4^{2} + 1 0^{2}

Simplify

2 4^{2} + 1 0^{2} : 676

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 676, c = - 676

676 = 26

- 676 = - 26

c = 26, c = - 26

\frac{x}{2} = 5

8 x^{2} + 2 x - 1

x - 7 = 4

\frac{1}{5} (x - 8) > x + 16

2 x - 22 < - 0.8

What are the solutions to the equation 24^2+10^2=c^2 ?
The solutions to the equation 24^2+10^2=c^2 are c=26,c=-26
Find the zeros of 24^2+10^2=c^2
The zeros of 24^2+10^2=c^2 are c=26,c=-26