What is expand (dx)/d (x=3cos(y)-sin(y)y_{2}) ?

The solution to expand (dx)/d (x=3cos(y)-sin(y)y_{2}) is (xdx)/d =3cos(y)-(y_{2}sin(y)dx)/d

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expand (dx)/d (x=3cos(y)-sin(y)y_{2})

expand

\frac{d x}{d} (x = 3 cos (y) - sin (y) y_{2})

\frac{x d x}{d} = 3 cos (y) - \frac{y _{2} sin ( y ) d x}{d}

Solution steps

\frac{d x}{d} (x = 3 cos (y) - sin (y) y_{2})

= \frac{d x}{d} (3 = x cos (y) - y_{2} sin (y))

Apply the distributive law:

a (b - c) = ab - a c

a = \frac{d x}{d}, b = x = 3 cos (y), c = sin (y) y_{2}

\frac{d x}{d} x = 3 cos (y) - \frac{d x}{d} sin (y) y_{2}

\frac{d x}{d} x = 3 cos (y) - \frac{d x}{d} y_{2} sin (y)

Simplify

\frac{d x}{d} x = 3 cos (y) - \frac{d x}{d} y_{2} sin (y) : \frac{x d x}{d} = 3 cos (y) - \frac{y _{2} sin ( y ) d x}{d}

\frac{x d x}{d} = 3 cos (y) - \frac{y _{2} sin ( y ) d x}{d}

(\frac{8 u}{5} + \frac{3 v ^{2}}{8}) (\frac{8 u}{5} - \frac{3 v ^{2}}{8})

(i - x)^{2} + c (x - c)^{2}

(1 + \frac{3 i}{n})^{2}

- 3 (2 a^{2} - 5 a - 4)^{2}

(1 + 5)^{14}

What is expand (dx)/d (x=3cos(y)-sin(y)y_{2}) ?
The solution to expand (dx)/d (x=3cos(y)-sin(y)y_{2}) is (xdx)/d =3cos(y)-(y_{2}sin(y)dx)/d