What is 1/2 (-1/6 cos(6x)-1/2 cos(2x)) ?

The solution to 1/2 (-1/6 cos(6x)-1/2 cos(2x)) is (-1/6 cos(6x)-1/2 cos(2x))/2

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simplify 1/2 (-1/6 cos(6x)-1/2 cos(2x))

simplify

\frac{1}{2} (- \frac{1}{6} cos (6 x) - \frac{1}{2} cos (2 x))

\frac{- \frac{1}{6} cos ( 6 x ) - \frac{1}{2} cos ( 2 x )}{2}

Solution steps

\frac{1}{2} (- \frac{1}{6} cos (6 x) - \frac{1}{2} cos (2 x))

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( - \frac{1}{6} cos ( 6 x ) - \frac{1}{2} cos ( 2 x ) )}{2}

Apply rule:

1 \cdot a = a

1 \cdot (- \frac{1}{6} cos (6 x) - \frac{1}{2} cos (2 x)) = (- \frac{1}{6} cos (6 x) - \frac{1}{2} cos (2 x))

= \frac{- \frac{1}{6} cos ( 6 x ) - \frac{1}{2} cos ( 2 x )}{2}

\frac{2 x}{( 2 x - 1 ) ^{2}}

\frac{( ( - 1 ) ^{n} \cdot ( e ^{s} - 1 ) \cdot e ^{- n s - s} )}{s}

(x^{2} + 1 + x)^{2}

2 - x^{2} (2 - x^{2})

(x - 2 i) (x + 2 i) (x - 3)^{2}

What is 1/2 (-1/6 cos(6x)-1/2 cos(2x)) ?
The solution to 1/2 (-1/6 cos(6x)-1/2 cos(2x)) is (-1/6 cos(6x)-1/2 cos(2x))/2