What is expand (z+16)/(z^2(z-1)) ?

The solution to expand (z+16)/(z^2(z-1)) is (z+16)/(z^3-z^2)

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expand (z+16)/(z^2(z-1))

expand

\frac{z + 16}{z ^{2} ( z - 1 )}

\frac{z + 16}{z ^{3} - z ^{2}}

Solution steps

\frac{z + 16}{z ^{2} ( z - 1 )}

Expand

z^{2} (z - 1) : z^{3} - z^{2}

= \frac{z + 16}{z ^{3} - z ^{2}}

\frac{( 3 x ^{2} + 4 )}{( x - 2 ) ^{2}}

\frac{x ( s + 12 )}{s ^{2} + 12 s + 36}

\frac{1}{( 1 + x ) ^{6}}

- 7 x^{2} l e f t (x y + 3 x^{5} y)

(y^{4} + k x y^{4} - x^{3}) d x

What is expand (z+16)/(z^2(z-1)) ?
The solution to expand (z+16)/(z^2(z-1)) is (z+16)/(z^3-z^2)