What is expand ((x+2)(x-4))/(2(x+3)(x-2)) ?

The solution to expand ((x+2)(x-4))/(2(x+3)(x-2)) is (x^2-2x-8)/(2x^2+2x-12)

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expand ((x+2)(x-4))/(2(x+3)(x-2))

expand

\frac{( x + 2 ) ( x - 4 )}{2 ( x + 3 ) ( x - 2 )}

\frac{x ^{2} - 2 x - 8}{2 x ^{2} + 2 x - 12}

Solution steps

\frac{( x + 2 ) ( x - 4 )}{2 ( x + 3 ) ( x - 2 )}

Expand

2 (x + 3) (x - 2) : 2 x^{2} + 2 x - 12

= \frac{( x + 2 ) ( x - 4 )}{2 x ^{2} + 2 x - 12}

Expand

(x + 2) (x - 4) : x^{2} - 2 x - 8

= \frac{x ^{2} - 2 x - 8}{2 x ^{2} + 2 x - 12}

\frac{( - 1 ) ^{n} - 1}{n ^{2}}

\frac{c}{s ( t s + 1 ) ^{2}}

\frac{( 3 x - 5 3 ) ( 5 - x )}{2}

f, f = x \cdot e^{- x} + δ (x - 4)

(x - \frac{v}{2})^{2}

What is expand ((x+2)(x-4))/(2(x+3)(x-2)) ?
The solution to expand ((x+2)(x-4))/(2(x+3)(x-2)) is (x^2-2x-8)/(2x^2+2x-12)