What is (sqrt(2x-1)-sqrt(5x-4))^2 ?

The solution to (sqrt(2x-1)-sqrt(5x-4))^2 is 7x-2sqrt(2x-1)sqrt(5x-4)-5

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simplify (sqrt(2x-1)-sqrt(5x-4))^2

simplify

(2 x - 1 - 5 x - 4)^{2}

7 x - 2 2 x - 1 5 x - 4 - 5

Solution steps

(2 x - 1 - 5 x - 4)^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(2 x - 1 - 5 x - 4)^{2} = (2 x - 1)^{2} - 2 2 x - 1 5 x - 4 + (5 x - 4)^{2}

= (2 x - 1)^{2} - 2 2 x - 1 5 x - 4 + (5 x - 4)^{2}

Simplify

(2 x - 1)^{2} - 2 2 x - 1 5 x - 4 + (5 x - 4)^{2} : 7 x - 2 2 x - 1 5 x - 4 - 5

= 7 x - 2 2 x - 1 5 x - 4 - 5

(5 x - x^{2}) (2 x - 3) d x

\frac{4 ( x ^{2} + x + 4 )}{( 2 x + 1 ) ^{2}}

a (- e^{- x} cos (x) - e^{- x} sin (x))

\frac{\frac{d}{d x} ( x ^{3} ( x - 5 ) ^{2} )}{( x ^{2} + 4 ) ^{7}}

f, f = e^{2 x} δ (x - 1) + x^{3}

What is (sqrt(2x-1)-sqrt(5x-4))^2 ?
The solution to (sqrt(2x-1)-sqrt(5x-4))^2 is 7x-2sqrt(2x-1)sqrt(5x-4)-5