What is expand x^{5/7}(x^{1/7}-x^{2/7}) ?

The solution to expand x^{5/7}(x^{1/7}-x^{2/7}) is x^{6/7}-x

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expand x^{5/7}(x^{1/7}-x^{2/7})

expand

x^{\frac{5}{7}} (x^{\frac{1}{7}} - x^{\frac{2}{7}})

x^{\frac{6}{7}} - x

Solution steps

x^{\frac{5}{7}} (x^{\frac{1}{7}} - x^{\frac{2}{7}})

Apply the distributive law:

a (b - c) = ab - a c

x^{\frac{5}{7}} (x^{\frac{1}{7}} - x^{\frac{2}{7}}) = x^{\frac{5}{7}} x^{\frac{1}{7}} - x^{\frac{5}{7}} x^{\frac{2}{7}}

= x^{\frac{5}{7}} x^{\frac{1}{7}} - x^{\frac{5}{7}} x^{\frac{2}{7}}

x^{\frac{5}{7}} x^{\frac{1}{7}} = x^{\frac{6}{7}}

x^{\frac{5}{7}} x^{\frac{2}{7}} = x

= x^{\frac{6}{7}} - x

(a x^{2} + b x - 2 a x - b + c) (d x^{2} + e x - 2 d x - e + f)

(5 + 3 i) (- 33 + 2 x π) i

\frac{7}{9 ( x + 2 ) ( 3 x + 6 )}

2 - (\frac{x - 2.5}{2} + 2.5 = 1)

ln (2) (x - 1) + \frac{1}{y}

What is expand x^{5/7}(x^{1/7}-x^{2/7}) ?
The solution to expand x^{5/7}(x^{1/7}-x^{2/7}) is x^{6/7}-x