What is (x/2-y/3)*(x/3+y/2) ?

The solution to (x/2-y/3)*(x/3+y/2) is ((3x-2y)(2x+3y))/(36)

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simplify (x/2-y/3)*(x/3+y/2)

simplify

(\frac{x}{2} - \frac{y}{3}) \cdot (\frac{x}{3} + \frac{y}{2})

\frac{( 3 x - 2 y ) ( 2 x + 3 y )}{36}

Solution steps

(\frac{x}{2} - \frac{y}{3}) (\frac{x}{3} + \frac{y}{2})

Simplify

\frac{x}{2} - \frac{y}{3} : \frac{3 x - 2 y}{6}

= \frac{3 x - 2 y}{6} (\frac{x}{3} + \frac{y}{2})

Simplify

\frac{x}{3} + \frac{y}{2} : \frac{2 x + 3 y}{6}

= \frac{3 x - 2 y}{6} \cdot \frac{2 x + 3 y}{6}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 3 x - 2 y ) ( 2 x + 3 y )}{6 \cdot 6}

Multiply the numbers:

6 \cdot 6 = 36

= \frac{( 3 x - 2 y ) ( 2 x + 3 y )}{36}

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\frac{41 ( 1 + r a c ^{2} )}{20}

What is (x/2-y/3)*(x/3+y/2) ?
The solution to (x/2-y/3)*(x/3+y/2) is ((3x-2y)(2x+3y))/(36)