What is expand-(e^{nθ}(-ne^{-nθ}θ-e^{-nθ}))/n ?

The solution to expand-(e^{nθ}(-ne^{-nθ}θ-e^{-nθ}))/n is θ+1/n

Popular >

expand-(e^{nθ}(-ne^{-nθ}θ-e^{-nθ}))/n

expand

- \frac{e ^{n θ} ( - n e ^{- n θ} θ - e ^{- n θ} )}{n}

θ + \frac{1}{n}

Solution steps

- \frac{e ^{n θ} ( - n e ^{- n θ} θ - e ^{- n θ} )}{n}

Expand

e^{n θ} (- n e^{- n θ} θ - e^{- n θ}) : - n θ - 1

= - \frac{- n θ - 1}{n}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- n θ - 1}{n} = - (- \frac{n θ}{n}) - (- \frac{1}{n})

= - (- \frac{n θ}{n}) - (- \frac{1}{n})

Apply rule

- (- a) = a

= \frac{n θ}{n} + \frac{1}{n}

Cancel

\frac{n θ}{n} : θ

= θ + \frac{1}{n}

tan (\frac{π}{3} - x)

(x + 5) (2 x - 35)

lo g_{12} (\frac{y ^{4}}{z m ^{4}})

\frac{( ( x ^{3} - 2 x ) ^{2} - 1 )}{x ^{2} - 1}

x^{\frac{5}{2}} (4 - x)

What is expand-(e^{nθ}(-ne^{-nθ}θ-e^{-nθ}))/n ?
The solution to expand-(e^{nθ}(-ne^{-nθ}θ-e^{-nθ}))/n is θ+1/n