What is expand (x-2)(x^2+2x+4)' ?

The solution to expand (x-2)(x^2+2x+4)' is x(x^2+2x+4)'-2(x^2+2x+4)'

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x-2)(x^2+2x+4)'

expand

(x - 2) (x^{2} + 2 x + 4)^{'}

x (x^{2} + 2 x + 4)' - 2 (x^{2} + 2 x + 4)'

Solution steps

(x - 2) (x^{2} + 2 x + 4)^{'}

Apply the distributive law:

a (b - c) = ab - a c

a = (x^{2} + 2 x + 4)^{'}, b = x, c = 2

= (x^{2} + 2 x + 4)^{^{'}} x - (x^{2} + 2 x + 4)^{^{'}} 2

= x (x^{2} + 2 x + 4)^{^{'}} - 2 (x^{2} + 2 x + 4)^{^{'}}

3 (x cos (θ) - y sin (θ) (x sin (θ) + y cos (θ)))

\frac{( x ^{2} + 1 ) ^{2}}{x ^{2} - 1}

x (x - y) + (z)

lo g_{10} (a^{9} b)

s im p l^{12} (\frac{8 x}{4} - 3)

What is expand (x-2)(x^2+2x+4)' ?
The solution to expand (x-2)(x^2+2x+4)' is x(x^2+2x+4)'-2(x^2+2x+4)'