What is expand xY'(x)+x^{4(x-Y(x))^2} ?

The solution to expand xY'(x)+x^{4(x-Y(x))^2} is xY'(x)+x^{4x^2-8xY(x)+4Y(x)^2}

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expand xY'(x)+x^{4(x-Y(x))^2}

expand

x Y^{'} (x) + x^{4 (x - Y (x))^{2}}

x Y' (x) + x^{4 x^{2} - 8 x Y (x) + 4 Y (x)^{2}}

Solution steps

x Y^{'} (x) + x^{4 (x - Y (x))^{2}}

x^{4 (x - Y (x))^{2}} = x^{4 x^{2} - 8 x Y (x) + 4 Y (x)^{2}}

= x Y^{^{'}} (x) + x^{4 x^{2} - 8 x Y (x) + 4 Y (x)^{2}}

\frac{( a + b - a - b ) ^{2}}{2 b}

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\frac{4 ( 3 q - 10 )}{3}

What is expand xY'(x)+x^{4(x-Y(x))^2} ?
The solution to expand xY'(x)+x^{4(x-Y(x))^2} is xY'(x)+x^{4x^2-8xY(x)+4Y(x)^2}