What is expand (dy)/y (-3,-5)(0,10)'' ?

The solution to expand (dy)/y (-3,-5)(0,10)'' is -3*(dy)/y (0*10,)'',-5*(dy)/y (0*10,)''

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expand (dy)/y (-3,-5)(0,10)''

expand

\frac{d y}{y} (- 3, - 5) (0, 10)^{''}

- 3 \cdot \frac{d y}{y} (0 \cdot 10,)'', - 5 \cdot \frac{d y}{y} (0 \cdot 10,)''

Solution steps

\frac{d y}{y} (- 3, - 5) (0, 10)^{''}

= (- 3, - 5) \frac{d y}{y} (0 \cdot 10,)^{^{''}}

Apply the distributive law:

a (b - c) = ab - a c

a = \frac{d y}{y} (0, 10)^{''}, b = - 3,, c = 5

= \frac{d y}{y} (0, 10)^{^{''}} (- 3,) - \frac{d y}{y} (0, 10)^{^{''}} 5

Apply minus-plus rules

+ (- a) = - a

= - 3 \cdot \frac{d y}{y} (0 \cdot 10,)^{^{''}}, - 5 \cdot \frac{d y}{y} (0 \cdot 10,)^{^{''}}

\frac{1}{5} (3 ln \frac{x ^{2}}{4} + 1 + 2 arctan (\frac{x}{2}))

\frac{3 x ^{3} + 2 x - 1}{x ( x + 1 ) ( x - 7 )}

(- sin (t) + cos (t)) \cdot (- cos (t) - sin (t))

(1 + \frac{1}{s ^{2}}) (\frac{s ^{3}}{2})

(e^{- 3 (x - y)} + cos (x - y)) (e^{- 3 x} + e^{2 x})

What is expand (dy)/y (-3,-5)(0,10)'' ?
The solution to expand (dy)/y (-3,-5)(0,10)'' is -3*(dy)/y (0*10,)'',-5*(dy)/y (0*10,)''