What is (1/4-x)(1/4+x) ?

The solution to (1/4-x)(1/4+x) is ((-4x+1)(4x+1))/(16)

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simplify (1/4-x)(1/4+x)

simplify

(\frac{1}{4} - x) (\frac{1}{4} + x)

\frac{( - 4 x + 1 ) ( 4 x + 1 )}{16}

Solution steps

(\frac{1}{4} - x) (\frac{1}{4} + x)

Simplify

\frac{1}{4} - x : \frac{- 4 x + 1}{4}

= \frac{- 4 x + 1}{4} (\frac{1}{4} + x)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( - 4 x + 1 ) ( \frac{1}{4} + x )}{4}

Simplify

(- 4 x + 1) (\frac{1}{4} + x) : \frac{( - 4 x + 1 ) ( x \cdot 4 + 1 )}{4}

= \frac{\frac{( - 4 x + 1 ) ( x \cdot 4 + 1 )}{4}}{4}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( - 4 x + 1 ) ( x \cdot 4 + 1 )}{4 \cdot 4}

Multiply the numbers:

4 \cdot 4 = 16

= \frac{( - 4 x + 1 ) ( x \cdot 4 + 1 )}{16}

= \frac{( - 4 x + 1 ) ( 4 x + 1 )}{16}

80 (10 + 1)

2 (- 5 + 5)

- \frac{9}{2} - 8

(x^{2} - x)^{2}

x^{2} (1 - \frac{2}{x})