What is expand (v-1)/((3v-5)(5v^2+4v)) ?

The solution to expand (v-1)/((3v-5)(5v^2+4v)) is (v-1)/(15v^3-13v^2-20v)

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expand (v-1)/((3v-5)(5v^2+4v))

expand

\frac{v - 1}{( 3 v - 5 ) ( 5 v ^{2} + 4 v )}

\frac{v - 1}{15 v ^{3} - 13 v ^{2} - 20 v}

Solution steps

\frac{v - 1}{( 3 v - 5 ) ( 5 v ^{2} + 4 v )}

Expand

(3 v - 5) (5 v^{2} + 4 v) : 15 v^{3} - 13 v^{2} - 20 v

= \frac{v - 1}{15 v ^{3} - 13 v ^{2} - 20 v}

\frac{f t}{x ( 4 x + 1 ) ( a x + b + ( 4 x + 3 ) )}

(1 + sin (x))^{3}

2 (5 + 7)

- (6 x + 6) sin (3 x^{2} + 3 x)

\frac{( x ^{2} + x ^{2} )}{( 2 - x ^{2} )}

What is expand (v-1)/((3v-5)(5v^2+4v)) ?
The solution to expand (v-1)/((3v-5)(5v^2+4v)) is (v-1)/(15v^3-13v^2-20v)