What is expand ((x+2)(x^2-2x+4))/(x^3) ?

The solution to expand ((x+2)(x^2-2x+4))/(x^3) is 1+8/(x^3)

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expand ((x+2)(x^2-2x+4))/(x^3)

expand

\frac{( x + 2 ) ( x ^{2} - 2 x + 4 )}{x ^{3}}

1 + \frac{8}{x ^{3}}

Solution steps

\frac{( x + 2 ) ( x ^{2} - 2 x + 4 )}{x ^{3}}

Expand

(x + 2) (x^{2} - 2 x + 4) : x^{3} + 8

= \frac{x ^{3} + 8}{x ^{3}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} + 8}{x ^{3}} = \frac{x ^{3}}{x ^{3}} + \frac{8}{x ^{3}}

= \frac{x ^{3}}{x ^{3}} + \frac{8}{x ^{3}}

Apply rule

\frac{a}{a} = 1

\frac{x ^{3}}{x ^{3}} = 1

= 1 + \frac{8}{x ^{3}}

(1 - cos (6 x))^{2}

1 + \frac{20.05 ( s + 7.28 )}{( s ^{2} + 8 s + 15 ) ( s + 19.42 )}

\frac{n ( 3 n + 5 )}{4 ( n + 1 ) ( n + 2 )}

(x - sin (x)) (1 - cos (x))

\frac{( 2 + h ) ^{3}}{h}

What is expand ((x+2)(x^2-2x+4))/(x^3) ?
The solution to expand ((x+2)(x^2-2x+4))/(x^3) is 1+8/(x^3)