What are the solutions to the equation -x^2+x+3=0 ?

The solutions to the equation -x^2+x+3=0 are x=-(-1+sqrt(13))/2 ,x=(1+sqrt(13))/2

Find the zeros of -x^2+x+3=0

The zeros of -x^2+x+3=0 are x=-(-1+sqrt(13))/2 ,x=(1+sqrt(13))/2

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- x^{2} + x + 3 = 0

x = - \frac{- 1 + 13}{2}, x = \frac{1 + 13}{2}

Solution steps

- x^{2} + x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 3}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 3 = 13

x_{1, 2} = \frac{- 1 \pm 13}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 13}{2 ( - 1 )}, x_{2} = \frac{- 1 - 13}{2 ( - 1 )}

x = \frac{- 1 + 13}{2 ( - 1 )} : - \frac{- 1 + 13}{2}

x = \frac{- 1 - 13}{2 ( - 1 )} : \frac{1 + 13}{2}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 13}{2}, x = \frac{1 + 13}{2}

(\frac{5}{3})^{- 2}

π \cdot 8^{2}

- 4 j + 2 - 4 j = 3 - 11 j - 6

- 4 x + 3 < - 2 x - 7

\frac{10}{12} + \frac{1}{4}

What are the solutions to the equation -x^2+x+3=0 ?
The solutions to the equation -x^2+x+3=0 are x=-(-1+sqrt(13))/2 ,x=(1+sqrt(13))/2
Find the zeros of -x^2+x+3=0
The zeros of -x^2+x+3=0 are x=-(-1+sqrt(13))/2 ,x=(1+sqrt(13))/2