What is expand 1/(3(6x^2+3x-9)) ?

The solution to expand 1/(3(6x^2+3x-9)) is 1/(18x^2+9x-27)

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expand 1/(3(6x^2+3x-9))

expand

\frac{1}{3 ( 6 x ^{2} + 3 x - 9 )}

\frac{1}{18 x ^{2} + 9 x - 27}

Solution steps

\frac{1}{3 ( 6 x ^{2} + 3 x - 9 )}

Expand

3 (6 x^{2} + 3 x - 9) : 18 x^{2} + 9 x - 27

= \frac{1}{18 x ^{2} + 9 x - 27}

(m g r = m g h + \frac{m g h}{2}) \cdot \frac{1}{m g}

h (2 x + 2 h + 6 + 2 x + 6)

e^{2 x} (e^{2 x} + 2 e^{2 x} x)

sin (x) (sin (x) - 6) + 4

(x - 10) (\frac{4}{x - 10} + 4 (100 - x))

What is expand 1/(3(6x^2+3x-9)) ?
The solution to expand 1/(3(6x^2+3x-9)) is 1/(18x^2+9x-27)