What is expand (x^2-y)y''(x) ?

The solution to expand (x^2-y)y''(x) is x^2y''(x)-y''(x)y

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expand (x^2-y)y''(x)

expand

(x^{2} - y) y^{''} (x)

x^{2} y'' (x) - y'' (x) y

Solution steps

(x^{2} - y) y^{''} (x)

Apply the distributive law:

a (b - c) = ab - a c

a = y^{''} (x), b = x^{2}, c = y

= y^{^{''}} (x) x^{2} - y^{^{''}} (x) y

= x^{2} y^{^{''}} (x) - y^{^{''}} (x) y

+ y (1 - x^{2}) d y

\frac{( z + J ^{2} ) ( z - 14 ) 5}{z - 14 + J ^{2}}

(x - cos (\frac{2 π}{7})) (x - cos (\frac{4 π}{7})) (x - cos (\frac{6 π}{7}))

(- e^{t} sin (t) + e^{t} cos (t))^{2} + cos^{2} (t)

\frac{cos ^{2} ( x ) - 3}{2 x ( cos ( x ) + 1 )}

What is expand (x^2-y)y''(x) ?
The solution to expand (x^2-y)y''(x) is x^2y''(x)-y''(x)y