What is expand-(6(3x^2-1))/((x^2+1)^3) ?

The solution to expand-(6(3x^2-1))/((x^2+1)^3) is -(18x^2-6)/(x^6+3x^4+3x^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-(6(3x^2-1))/((x^2+1)^3)

expand

- \frac{6 ( 3 x ^{2} - 1 )}{( x ^{2} + 1 ) ^{3}}

- \frac{18 x ^{2} - 6}{x ^{6} + 3 x ^{4} + 3 x ^{2} + 1}

Solution steps

- \frac{6 ( 3 x ^{2} - 1 )}{( x ^{2} + 1 ) ^{3}}

(x^{2} + 1)^{3} = x^{6} + 3 x^{4} + 3 x^{2} + 1

= - \frac{6 ( 3 x ^{2} - 1 )}{x ^{6} + 3 x ^{4} + 3 x ^{2} + 1}

Expand

6 (3 x^{2} - 1) : 18 x^{2} - 6

= - \frac{18 x ^{2} - 6}{x ^{6} + 3 x ^{4} + 3 x ^{2} + 1}

\frac{d}{d y} ((x) ((x^{2} - 1)^{4}))

(\frac{2 x ^{4}}{y} - \frac{y ^{2}}{x})^{10}

(r - r cos (θ))^{2}

2 (32 + 2)

7 (1 + 6 sin (θ))^{2}

What is expand-(6(3x^2-1))/((x^2+1)^3) ?
The solution to expand-(6(3x^2-1))/((x^2+1)^3) is -(18x^2-6)/(x^6+3x^4+3x^2+1)