What is expand (2x+2yy'(x)=0) 1/2 ?

The solution to expand (2x+2yy'(x)=0) 1/2 is x+yy'(x)=0

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expand (2x+2yy'(x)=0) 1/2

expand

(2 x + 2 y y^{'} (x) = 0) \frac{1}{2}

x + yy' (x) = 0

Solution steps

(2 x + 2 y y^{'} (x) = 0) \frac{1}{2}

= \frac{1}{2} (2 x + 2 \cdot 0 = y y^{^{'}} (x))

Apply the distributive law:

a (b + c) = ab + a c

a = \frac{1}{2}, b = 2 x, c = 2 y y^{'} (x) = 0

\frac{1}{2} \cdot 2 x + \frac{1}{2} \cdot 2 y y^{^{'}} (x) = 0

2 \cdot \frac{1}{2} x + 2 \cdot \frac{1}{2} y y^{^{'}} (x) = 0

Expand

2 \cdot \frac{1}{2} x + 2 \cdot \frac{1}{2} y y^{'} (x) : x + y y^{'} (x)

x + y y^{^{'}} (x) = 0

(1 + t)^{2} (1 - t)^{3}

37 - 2 (π x + π)^{3}

\frac{37}{( s ^{2} + 1 ) ( s + 6 )}

(x^{2} - x y) (x + y)

(x + 2) (x^{2} - 3 x)

What is expand (2x+2yy'(x)=0) 1/2 ?
The solution to expand (2x+2yy'(x)=0) 1/2 is x+yy'(x)=0