What is (a/(x+3)+b/(x-2))(x+3)(x-3) ?

The solution to (a/(x+3)+b/(x-2))(x+3)(x-3) is ((ax-2a+bx+3b)(x-3))/(x-2)

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simplify (a/(x+3)+b/(x-2))(x+3)(x-3)

simplify

(\frac{a}{x + 3} + \frac{b}{x - 2}) (x + 3) (x - 3)

\frac{( a x - 2 a + b x + 3 b ) ( x - 3 )}{x - 2}

Solution steps

(\frac{a}{x + 3} + \frac{b}{x - 2}) (x + 3) (x - 3)

Join

\frac{a}{x + 3} + \frac{b}{x - 2} : \frac{a x - 2 a + b x + 3 b}{( x + 3 ) ( x - 2 )}

= \frac{a x - 2 a + b x + 3 b}{( x + 3 ) ( x - 2 )} (x + 3) (x - 3)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( a x - 2 a + b x + 3 b ) ( x + 3 ) ( x - 3 )}{( x + 3 ) ( x - 2 )}

Cancel the common factor:

x + 3

= \frac{( a x - 2 a + b x + 3 b ) ( x - 3 )}{x - 2}

(1.02)^{8}

\frac{( 2 x + 5 ) ^{2}}{x}

(3 + cos (x))^{3}

(z - 2 i) (z + 2 i)^{2}

\frac{1}{s ( s ^{2} + 5 s + 4 )}

What is (a/(x+3)+b/(x-2))(x+3)(x-3) ?
The solution to (a/(x+3)+b/(x-2))(x+3)(x-3) is ((ax-2a+bx+3b)(x-3))/(x-2)