What are the solutions to the equation x^2-8x+20=5 ?

The solutions to the equation x^2-8x+20=5 are x=5,x=3

Find the zeros of x^2-8x+20=5

The zeros of x^2-8x+20=5 are x=5,x=3

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x^{2} - 8 x + 20 = 5

x = 5, x = 3

Solution steps

x^{2} - 8 x + 20 = 5

Move

5

to the left side

x^{2} - 8 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

x_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

x = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 5, x = 3

a - 15 = 4 a - 3

x^{3} - 6 x^{2} > 0

\frac{7 0 ^{\frac{1}{3}}}{1 4 ^{\frac{1}{3}}}

- 8 x - 9 = - 21

(3 x + 2)^{2} - 5 (3 x + 2) = 24

What are the solutions to the equation x^2-8x+20=5 ?
The solutions to the equation x^2-8x+20=5 are x=5,x=3
Find the zeros of x^2-8x+20=5
The zeros of x^2-8x+20=5 are x=5,x=3