What is expand f(x,y= 3/2)(x^2+y^2) ?

The solution to expand f(x,y= 3/2)(x^2+y^2) is x^2f(3/2 ,=xy)+y^2f(3/2 ,=xy)

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expand f(x,y= 3/2)(x^2+y^2)

expand

f (x, y = \frac{3}{2}) (x^{2} + y^{2})

x^{2} f (\frac{3}{2}, = x y) + y^{2} f (\frac{3}{2}, = x y)

Solution steps

f (x, y = \frac{3}{2}) (x^{2} + y^{2})

= f (\frac{3}{2}, = x y) (x^{2} + y^{2})

Apply the distributive law:

a (b + c) = ab + a c

a = f (x, y = \frac{3}{2}), b = x^{2}, c = y^{2}

= f (x, y = \frac{3}{2}) x^{2} + f (x, y = \frac{3}{2}) y^{2}

= x^{2} f (\frac{3}{2}, = x y) + y^{2} f (\frac{3}{2}, = x y)

\frac{x ^{2} ( 3 - x )}{4}

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\frac{( x + 4 ) ( x - 8 )}{3}

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\frac{a ( a + 12 )}{4}

What is expand f(x,y= 3/2)(x^2+y^2) ?
The solution to expand f(x,y= 3/2)(x^2+y^2) is x^2f(3/2 ,=xy)+y^2f(3/2 ,=xy)